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doesnt look so hard but can't solve it ffs help plz

2+2=5

2+2 is 7. damn

A

nasil yaptin soyle LUTFEEEEEEN
A dogru

thats easy wtf

it's A

Its D) Thank me l8r

but how did you solve

zzzzzz 10th grade u 12yr old

im 11th grade and trying to study home alone, 3 months left for upcoming exam plz help

it is e
ecuation of first circle equation - second

i know those but still can't solve this question

sorry i thought you have 5 integral to solves

C
you're looking at the negative because its all below x axis. look at negative of big circle which is integral from -1 to 1 of -(sqrt(9-x^2)) (call this g) and then subtracting the semi-circle which is -sqrt((1-x^2)) (call this f)
so: g-f to find area and you get sqrt(1-x^2) - (sqrt(9-x^2)
and you can workout formula of circle easily by x^2+y^2 = r^2 where r is radius. you can rearrange to find y by -x^2 and taking + and - sqrt. discard the + sqrt because you're only looking below the x-axis

sorry for bothering again but how did you find sqrt(9-x^2) and sqrt(1-x^2)? i mean i'm not so bad at graphs but didn't get this one

radius of big circle = 3. formula for circle = (x-a)^2+(y-b)^2=r^2. since the origin of both circles is at 0,0 a and b= 0. so the formula for the big circle is x^2+y^2=3^2 and the formula for the small circle is x^2+y^2=1^2. find y by rearranging using basic algebra. you get for the big circle y^2=3^2-x^2 = 9-x^2. to find y you just take the square root and get sqrt(q-x^2). same process to work out the second circle.
it might be A. could've messed up with the negatives somewhere

thanks for your effort

the answer is A by the way.

B

S =sin(x+a)ex(xdx)

C
You want to subtract the two circles to find the area between. Since you're taking the bottom part of the integral, you want to take the negative parts of the square roots. So you'd take the integral from -1 to 1 of -sqrt(9-x^2) - (-sqrt(1-x^2)), which if you simplify out comes out to C.

Not C as the result is negative.

it's asking for the integral, not the area

Well, maybe you are right, in my country we often use the letter S for Surface and A for Aire (area).

yeah but your country is a fucking shithole

wtf respect france?

Can you remind me how many players from Netherlands are present at the major?

yeah but your country is a fucking shithole

ez :)
The bigger circle equation:
c1: x^2 + y^2 = 3^2
The smaller circle equation:
c2: x^2 + y^2 = 1^2
Now, just express the y from both:
f1: y = abs(sqrt(3^2 - x^2))
f2: y = abs(sqrt(1^2 - x^2))
Note the absolute value, which accounts for the fact that you can either count the upper half or the bottom half of the circle. Since you are counting the bottom (negative) part (see here > revisionmaths.com/advanced-level-maths-r..) both expressions would turn to their negative versions:
f1: y = - sqrt(3^2 - x^2)
f2: y = - sqrt(1^2 - x^2)
And last part, just take [bigger circle area] - [smaller circle area] = integral from -1 to 1 [ f1(x) - f2(x) ]
= integral from -1 to 1 [ - sqrt(3^2 - x^2) - (- sqrt(1^2 - x^2)) ]
= integral from -1 to 1 [ sqrt(1^2 - x^2) - sqrt(3^2 - x^2) ]
= integral from -1 to 1 [ sqrt(1 - x^2) - sqrt(9 - x^2) ]
Which is the A option :0)

bhbbhabahbhabahaahahahahah
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