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Hong Kong 131_IQ 
A company recive 35 packages with light bulbs. In each pack there is 10 light bulbs, 2 of the light bulbs in each package has an error (witch cant bee seen). From each pack there is 3 diffrent bulbs picked out What are the estimated chance that we will pick more than 0.35 light bulbs with the error? 1. 0,9471 2. 0,0078 3. 0,6110 4. 0,9922
2019-04-25 10:00
witch cant bee seen
2019-04-25 10:02
what ever dude i need the anwer
2019-04-25 10:03
Denmark God_of_Wisdom 
None. I use LED.
2019-04-25 10:03
good 4 you my man
2019-04-25 10:03
Denmark God_of_Wisdom 
That's right, so get the fuck outa here with your light bulbs before I shove it up your ass and bring me some r8/18+ threads.
2019-04-25 10:05
Man, i wont do ur homework 😎
2019-04-25 10:03
i have to pass this test to take finals and i cant do this excercise cuz i play to much cs go ... and didnt go to class for this lecture...
2019-04-25 10:04
And we should reward such behaviour by giving you the answer?
2019-04-25 10:06
I guess thats ur problem right
2019-04-25 10:07
you can look up how to solve this in 5 minutes on wikipedia
2019-04-25 10:26
North America Snaxer 
I can help with calculus. not this tho
2019-04-25 10:06
Denmark jkaemmeister 
binomials bruh
2019-04-25 10:07
oskarJ | 
Czech Republic y0fl0w 
You'll fail the test, hf
2019-04-25 10:08
Since all packages are the same, the number of packages doesn't matter anyway And none of these 4 answers is the right one
2019-04-25 10:10
Correct if my iq is low, but picking more than 0.35 💡 means at least one right ? Cause if so, it’s the opposite of not picking any which is ez mens))😎
2019-04-25 10:20
maybe he means the chance that 35% of picked light bulbs has the error? idk. seems like standard statistics question. should be easily solved with the book.
2019-04-25 10:25
Yes maybe. But still ez mens 😎
2019-04-25 10:28
it isnt a standard problem.
2019-04-25 11:04
its a variation on a standard problem, ive done like a dozen versions of it in probability & statistics class in the standard version the total error rate is given instead of the condition 2/10 broken bulbs per box but you still pick them random so its the same as 20% error rate also usually the question is what is the chance there will be 1 or more broken bulbs in a box
2019-04-25 14:58
yes, its a variation of the binomial distribution with the difference that you dont put the items "back in the box" its the hypergeometrical distribution and none of his answers are actually correct lol.
2019-04-25 15:13
we're not helping with ur maths homework
2019-04-25 10:25
i need a calculator
2019-04-25 10:29
"we will pick more than 0.35 light bulbs" It must be 35% You see the question is wrongly stated.
2019-04-25 10:36
Google binomial chance
2019-04-25 10:36
0.99477019784810140000 its a hypergeometrical distribution
2019-04-25 10:41
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