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The displacement (in meters) of a particle moving in a straight line is given by the equation of motion
s = 4/t2,
where t is measured in seconds. Find the velocity of the particle at times
t = a, t = 1, t = 2, and t = 3.
plz need help on math homework. I believe you use the formula
Lim (s(a+h) -s(a)) / (h)
h->0

math in 2019

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step by step here
slader.com/discussion/question/the-displ..

Btw, idk if this is correct, i'm an engineer, but i did calculus like 6 years ago

0

How is this equation homogenic? We have s in meters and t in seconds so u say meters=1/s^2?

y=mx+b

-8/a^3, -8, -1, -8/27 metres per second
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just did

+1

If you differentiate the displacement equation with respect to t, you'll get the velocity equation v(t) = -8/t^3
Substitute in the values for t and there you go.
Notice that the velocity is strictly decreasing and will eventually reach 0, this is logical since from the displacement equation as t approaches infinity, the displacement also tends towards 0.