Just 1v1 your math teacher
do we count bottle as a cylinder ?
34cm •3? Idk I’m bad at math
Bro if you're having issues with such questions you should reconsider your schedule and focus on studying math lol
The height should be just 34*3 if the width dooesnt change. If it does then you would need to know the other width too iirc. So 102 is probs the correct answer. Or im being extremelly stupid rn. Which is probs the case
Pretty sure height is approximately 49. I am on mobile so I can't type my shit. Will write it on paper and upload image.
dude be on an exam and gets his phone out TO ASK HLTV
Jesus, it took me like 5 minutes to figure this out. Fucking brain fog
are you a 4th grader or what?
102cm is the logical answer , but if width changes then shit idk
V1/V2=1/3
(pi*r1^2*h1) /(pi*r2^2*h2) =1/3
(r1^2*h1) /(r2^2*h2) =1/3
if h1/h2=k, then
k^3=1/3
k=(1/3)^(1/3)
h2=h1/k=h1*(3)^(1/3)=34*(3)^(1/3) cm
And yes, this is an April 1 joke, took my demented shitty brain this long to figure it out
Just think yourself or ask a relative don’t come here to ask
Lol it's etäopetus, just look at book mens. 😎
wtf you have tests during corona ?
Idk if you still need help but you should do it ?"cross" style?
0.5 = 34
1.5 = x
x = (1.5*34)/0.5 = 102
Also you could just multiply 34 by 3 because 1.5/0.5=3
V of bottle is 2x*h , first bottles V=2x*0.34, r is density r=m/V, the drink is the same so r1=r2, m1/V1=m2/V2, 0,5/2x*0.34=1,5/2x*h , h=0.34*1,5/0,5= 1.02m, The height of the second one is 1.02m, if the proportions are not the same instead of x put in the proportions that it gives you.
1L = 500cm^3 ............... length = third root of 500cm^3 = 7,937
1.5L = 15000cm^3 ................. length = third root of 1500cm^3 = 11,447
ratio 11,447: 7,937 = 1,442
HEIGHT 34cm x 1,442 = 49,028cm
given its a real bottle and not just a cylinder and the proportions stay the same.
Not sure but
The formula to find the volume (or litres) of a cylinder is V(bottle) = pir^2h, where h is the height of the bottle (in metres) and r is the radius.
For 1st bottle, 0.5 = pir^2 x 0.34
Gotta rearrange to find for 'r'
0.5/0.34 = pir^2
(0.5/0.34)/pi = r^2
square-root((0.5/0.34)/pi) = r
Therefore, r = 0.68418036642371736800657643239874
Now, we want to find the height of the second bottle, so we have to rearrange V(bottle) = pir^2h to find h.
So, V(Bottle)/(pi(r^2)) = h
We know the V is 1.5 and r is the same as before, so just plug in the numbers:
1.5/(pi(0.68418036642371736800657643239874^2)) = 1.02
The second bottle is 1.02 metres high, or 102 centimetres :)
Thanks to everyone who helped me or tried to help me even if your answer was not the correct one! I have the question now done and I'll at least pass this class.
I don't know math isn't my strongest subject.
Write down the formulas then substitute
radius of base r = square root x ( 500 / 34 Pi ) in centimetres
than you have V = Pi x h x r2
height h = V / ( Pi x r2 )
h = 1500 / ( Pi x r2 )
or just multiply height by 3
so ez haha dog bullshit motherfucker asslick wanker
I would assume that the bottle is just a cylinder
a) calculate its radius (0.5l bottle)
b) upscale the cylinder til it reaches a volume of 1.5l (upscale the height and radius in the same proportions)
should be doable with an equation
how did you do it?
Lukion koeviikko cheat. :D Always trust hltv
I read 'meth' and immediately came here to help fellow men with their business but nvm
bruh imagine actually studying hahahaha, studying won't get you anywhere in life