CHINESE PPL COME
You should type it like this man.
2020-09-22 18:20
A year ago I would've been able to do that
Now I've forgotten
Depressing.
2020-09-22 18:20
just use calculator men wtf
2020-09-22 18:20
sperm broke my memory at this time in uni...
2020-09-22 18:21
thats an anti derivative so just do the opposite of differentiation
2020-09-22 18:24
Math God lol, and then its an equation for some random high school junior lmao
2020-09-22 18:24
Bro how old are you? I think i am so young to know that but i want to know when i will learn that.
2020-09-22 18:24
not that hard man, why are you on hltv just look at your math book xaxaxaa
2020-09-22 18:25
I think it's ((4x²-3)^8)/(8x*8)
2020-09-22 18:25
I can solve it. but the dx at the end makes no sense
2020-09-22 18:26
Oh i forgot differentials sorry
2020-09-22 18:37
Expand, integrate, reduce.
The expand is probably the worst part.
2020-09-22 18:40
what sadist is making you do this
if you have to solve it by hand, it would be easiest to turn (4x^2 -3)^7 into
(4x^2-3)(4x^2-3)(4x^2-3)(4x^2-3)(4x^2-3)(4x^2-3)(4x^2-3) and then multiply them all together, one at a time (very tedious)
then you will have a bunch of terms with + and - between them, which is easy to integrate and I shouldn't have to explain to you how to do that
unless there is some shortcut I forgot
2020-09-22 18:44
men use symbolab it simple derivative anyway
2020-09-22 18:45
The answer is:
integral(4 x^2 - 3)^7 dx = (16384 x^15)/15 - (86016 x^13)/13 + (193536 x^11)/11 - 26880 x^9 + 25920 x^7 - (81648 x^5)/5 + 6804 x^3 - 2187 x + constant
2020-09-22 18:49
This brings back memories. HL math days in highschool.
2020-09-22 18:54
more like 8th graders come.
2020-09-22 18:56
i have absolutely no clue
2020-09-22 18:56
reported for excluding brazilians
2020-09-22 18:57
Assume 4x^2-3 = y, differentiate both sides w.r.t x
d/dx (4x^2-3) = dy/dx
8x= dy/dx
dx = dy/8x
Your problem was
int (4x^2-3)^7 dx
substituting value of y and dx
int y^7 dy/8x
= 1/8x . y^8/8
resubstitute value of y and you get your answer (4x^2-3)^8/64x
btw this is so ez, you need to work upon your basics
2020-09-22 19:03
im dumb but i want to know how to solve this, if anyone knows, pls tell me too.
2020-09-22 19:03
PhD in math here, use Newton's binomial theorem. (4x^2-3)^7 = sum_{i=0}^7 n! / ( i! (n-i)! ) (4x^2)^i 3^(7-i). Using linearity of the integral you'll get sum_{i=0}^7 n! / ( i! (n-i)! ) 4^i 3^(7-i) x^(2i+1) / (2i+1)
2020-09-22 19:09
Yeah fuck this shit, today i had math final graduation exam , and in the first calculator free section we had this type of shit to figure out without calculator honestly wtf
2020-09-22 19:25
that's really aids to solve with any method, you could do integration by parts where u=(4x^2-3)^7 and v=1 then repeat 7 times to reduce, which will probably get you there faster than finding the polynomial
2020-09-22 19:26