mens ur nickname doesnt checks out mens
2020-11-24 11:48
remove smart from your name pls
is this like 6th grade?
2020-11-24 12:10
-3;3;0
absolute value doesn't affect value of x, just it's evolution
so yes, in bracket of absolute value can be negative number, only it changes minus to plus after you start working with it
2020-11-24 12:19
the outcome will always be >=0 with that |x|
2020-11-24 12:22
wtf is this? Is it 2mod*xmod*-3mod = 3 ?
Please send a photo of the question or write it properly i dont get it.
Wait a min, is it, 2mod*xmod + (-3mod) = 3?
2020-11-24 12:54
Is it |2x-3|= 3 or |2|x |-3| =3 ?
Its really a difference because if you had one mod it will be x € (0,3) but if not you just divide the mods and x = 3
2020-11-24 13:00
do you mean
I 2 IxI -3I
or I2I x I-3I
2020-11-24 13:02
|2|=2 ; |-3|=3
2*3*x=3 => x=0,5
2020-11-24 13:14
I was expecting some high level calculus math what the fuck is this
2020-11-24 13:20
yeah this is basic math
2|x|-3=+-3
take +
2|x|=6
|x|=3, x=+-3
2020-11-24 13:24
|x| = x if x>=0
|x| = -x if x<0
|x| is always positive.
Also no idea what your question is? How you wrote the equation isn't correct...
I'm gonna assume you wrote 2*x*|-3| = 3 <=> 6*x=3 <=> x = 3 / 6 <=> x = 1/2
2020-11-24 13:28
lets say x>=0
|2x-3| = 3
2x-3 = +- 3
case a)
2x-3 = 3
2x = 6
x= 3 (x should be greater than or equal to zero, acceptable answer)
case b)
2x-3 = -3
2x = 0
x = 0 (acceptable answer since x>=0)
lets say x<0
|2*(-1)x-3| = 3
-2x-3 = +-3
case a)
-2x-3 = 3
-2x = 6
x = -3 (acceptable since x<0)
case b)
-2x -3 = -3
2x = 0
x = 0 (not acceptable since x<0)
So final answer is x can be 3,0,-3
2020-11-24 13:30