ESEA All-Star nominees
ESEA has revealed the names of the players who have been nominated for the All-Star game between Europe and North America.
With the regular ESEA Invite season in both Europe and North America having come to an end, the top four teams from both regions are now looking forward to the global finals, which will take place from April 19th to 21st in Dallas.
Before the main tournament starts, however, there will be an All-Star game between the two regions, not only for bragging rights, but also for a better seeding in the team competition.
A panel of ESEA experts has convened to determine which two players from each of the attending teams are up for nomination in the All-Star game.
The community will now vote for one player from each team to defend their respective region. The losing players will then be placed in a separate poll, from which the fifth and sixth (backup) members will be picked.
|Team||Player One||Player Two|
||Patrik "f0rest" Lindberg||Christopher "GeT_RiGhT" Alesund|
|VeryGames||Nathan "NBK" Schmitt||Adil "ScreaM" Benrlitom|
|Virtus.pro||Mihail "Dosia" Stolyarov||Kiril "ANGE1" Karasiow|
|n!faculty||Azmican "asmo" B.||Benjamin "qk-Mantis" Oberlein|
||Spencer "hiko" Martin||Sam "DaZeD" Marine|
|Curse||Todd "anger" Williams||Tyler "Skadoodle" Latham|
|Dynamic||Jordan "n0thing" Gilbert||Keven "AZK" Lariviere|
||Francis "kiko" Lao||Kyle "flowsicK" Mendez|
The balloting period will be of just three days per team, with only one poll running at a time. You can now start voting for your North American All-Star team by choosing between the two Curse players who have been nominated: Todd "anger" Williams and Tyler "Skadoodle" Latham.
Curse finished in second place in the North American division, level on points with leaders Quantic Gaming but with the head-to-head disadvantage.
|Todd "anger" Williams||313||248||48|
|Tyler "Skadoodle" Latham||329||192||51|
To cast your vote, head over to ESEA's website. Remember that you only have three days to choose and that you need a Premium account to vote.